Question 340569
It has to be 2 different numbers.
x + x = 6 --> x = 3
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Then, you have (x + x)^2 = 20.  That's not what it says.
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x = 1 number
y = the other number
x + y = 6
x^2 + y^2 = 20 not (x+y)^2 = 20
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