Question 340494
(x+2)^2 + (y-2)^2= 9
(x-1)^2 + (y-2)^2=16 
----------------------
{{{(y-2)^2 = 9 - (x+2)^2 = 16 - (x-1)^2}}}
{{{9 - x^2 - 4x - 4 = 16 - x^2 + 2x - 1}}}
5 - 4x = 15 + 2x
-10 = 6x
x = -5/3
----------
Sub for x into either eqn and find 2 values for y.