Question 340391
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In general:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(t)\ =\ P_oe^{rt}]


So for 3.1% per year:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(t)\ =\ P_oe^{0.031t}]


For 1000 for 1 year:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(t)\ =\ 1000e^{0.031(1)}]


For 1000 for 2 years:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(t)\ =\ 1000e^{0.031(2)}]


I'll leave you alone to spend some quality time with your calculator.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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