Question 340390
Three consecutive even integers would be {{{N}}}, {{{N+2}}}, and {{{N+4}}}.
Find three consecutive even integers such that 
"6 times the sum of the first and the third""{{{6(N+(N+4))=6(2N+4)=12N+24}}}
"is" translates to "="
"8 less than 14 times the second":{{{14*(N+2)-8=14N+28-8=14N+20}}}
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{{{12N+24=14N+20}}}
Solve for {{{N}}}. 
Then find {{{N+2}}} and {{{N+4}}}.