Question 340254

Plug in {{{x=-3}}} to get {{{y=(1/3)x=(1/3)(-3)=(-3)/3=-1}}}



So when {{{x=-3}}}, {{{y=-1}}}



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Plug in {{{x=0}}} to get {{{y=(1/3)x=(1/3)(0)=(0)/3=0}}}



So when {{{x=0}}}, {{{y=0}}}



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Plug in {{{x=2}}} to get {{{y=(1/3)x=(1/3)(2)=(2)/3}}}



So when {{{x=2}}}, {{{y=2/3}}}



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Plug in {{{x=6}}} to get {{{y=(1/3)x=(1/3)(6)=(6)/3=2}}}



So when {{{x=6}}}, {{{y=2}}}



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Plug in {{{x=8}}} to get {{{y=(1/3)x=(1/3)(8)=(8)/3}}}



So when {{{x=8}}}, {{{y=8/3}}}



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