Question 340375
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Let *[tex \Large x] represent one of the numbers.  Then the other number must be *[tex \Large 40\ -\ x].


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ (40\ -\ x)\ =\ 11]


Solve for *[tex \Large x].  Subtract the *[tex \Large x] value from 40.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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