Question 340258
I believe your solution is as follows:


If you draw a red 5 out of a standard 52 card deck given it is not a face card or an ace, then the probability of success would be 2/32 = 1/18.


This is because you are given that the card drawn is not a face card or an ace.


There are 4 face cards plus an ace for each suit in the deck.


That's 5 cards per suit * 4 for a total of 20 cards that can be effectively removed from the deck because you are given that the card drawn will not be a face card or an ace.


Your universe of possible selections is now 32 rather than 52 because you are given that the card will not be a face card or an ace.


The matching probability would be drawing a total of 3 out of 2 dice.


The probability that can happen is 2 / 36 = 1 / 18 which is the same as drawing the red card out of a deck without the face cards or the ace in them.