Question 340261
From 6(c-2)=7(c-6),
let's multiply out first, and get
6c - 12 = 7c - 42
now we want all the c's on one side and all the numbers on the other...
so subtract 6c from both sides...
-12 = c - 42
now add 42 to both sides
30 = c
c = 30
You can check the solution by plugging it back into the original equation...