Question 38925
We can see that x = 1 is a solution of
x^3 + x - 2 = 0
but if we factor that expression by x - 1, we get
(x - 1)(x^2 + x + 2) = 0
and the second polynomial is not factorable...you have to use the quadratic...
so x = 1 and
x = (-1 ± i*sqrt(7)) / 2