Question 340037
{{{6-y = -y+2}}}
First, I would replace {{{y}}} with {{{x}}},
and write each side as an equation {{{z = f(x)}}}
{{{z = 6 - x}}}
{{{z = -x + 2}}}
Now I can plot both lines and see where they intersect
{{{ graph( 500, 500, -10, 10, -10, 10, -x + 6, -x + 2) }}} 
The lines are parallel, the slopes are both {{{-1}}}, so
there is no solution (place where the same {{{x}}} is on both lines,
and since I made {{{x = y}}}, no solution for {{{y}}} either