Question 340020
If I write {{{e^a = 2}}}
and {{{e^b = 8y}}},
then {{{a = ln(2)}}}and
{{{b = ln(8y)}}}
From the first 2 equations, I can say
{{{e^a * e^b = 16y}}}
{{{e^(a + b) = 16y}}} (from rules of exponents)
Another way to write this is
{{{ln(16y) = a + b}}}, or
{{{ln(16y) = ln(2) + ln(8y)}}}
This contradicts the assumption in the problem,
so the answer is no