Question 339928
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t)\ =\ -16t^2\ +\ 149t]


is only true if the ball was launched from the ground at 149 feet per second initial velocity.  Typically when you throw something upward, the ball is above the ground by a distance that is in proportion to the thrower's height.


Be that as it may, the function describes a parabola opening downward.  The maximum height is reached at the value of *[tex \Large t] for the vertex of the parabola.  Use *[tex \Large \frac{-b}{2a}] where *[tex \Large b\ = 149] and *[tex \Large a\ =\ -16]


By the way, 149 feet per second is roughly 101.5 miles per hour, very close to the top speed of a pitched baseball.  Find me the guy who can throw a ball straight up at that velocity.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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