Question 38898
Let the two odd integers be.
x, and x+2
Equation:

(x)(x+2)=4(x+x+2)-1
{{{x^2+2x=8x+8-1}}}
{{{x^2-6x-7=0}}}
{{{x = (-(-6) +- sqrt( (-6)^2-4*1*-7 ))/(2*1) }}} 
x=7
7+2=9
Hence, the two odd integers are 7 and 9.
Paul.