Question 339915
Since {{{tan(pi/3)=sqrt(3)}}}, this means that the inverse tangent of {{{sqrt(3)}}} is {{{pi/3}}}. Now just add {{{pi}}} to the answer to get {{{pi/3+pi=pi/3+3pi/3=4pi/3}}} (this rotates the angle 180 degrees)



So *[Tex \LARGE \tan^{-1}(\sqrt{3})=\frac{pi}{3}] or *[Tex \LARGE \tan^{-1}(\sqrt{3})=\frac{4pi}{3}] where the angle is in the range from 0 to {{{2pi}}}