Question 339866
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Let *[tex \Large x] represent Katie's age now.  Three years ago she was *[tex \Large x - 3].  When she is twice as old as she is now she will be *[tex \Large 2x] and that is equal to three times what she was three years ago, or *[tex \Large 3(x\ -\ 3)].


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3(x\ -\ 3)\ =\ 2x]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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