Question 339819
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You need to calculate: *[tex \LARGE \left(8\cr 3\right\)]


Where *[tex \LARGE \left(n\cr k\right\)] is the number of combinations of *[tex \Large n] things taken *[tex \Large k] at a time and is calculated by *[tex \Large \frac{n!}{k!(n\,-\,k)!}]


Which will give you the denominator of your probability fraction, i.e. the total number of possible outcomes.  Since only one of those outcomes is a success according to the parameters of your problem, the numerator of the probability fraction is 1.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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