Question 339836
one car 3 miles 40 mph  ----- t1 = 3/40 hours
second car 4 miles 50 mph----t2= 4/50 hours
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they form a right angle with intersection.
the distance between the cars = hypotenuse.
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{{{d^2 = (3/40)^2 + (4/50)^2}}}
Take square root of both sides
{{{ d =  sqrt((t1)^2+(t2)^2)}}}