Question 339835
Perpendicular lines have slopes that are negative reciprocals.
{{{m1*m2=-1}}}
{{{4*m2=-1}}}
{{{m2=-1/4}}}
Now use the slope-intercept form, {{{y=mx+b}}}
{{{y=-(1/4)x+b}}}
Use the point (2,-3) to solve for {{{b}}}.
{{{-3=-(1/4)(2)+b}}}
{{{-3=-1/2+b}}}
{{{b=-5/2}}}
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{{{highlight(y=-(1/4)x-5/2)}}}
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(2,-3,0.2),graph(300,300,-5,5,-5,5,4x+7,-(1/4)x-5/2))}}}