Question 338987
{{{((20x^5)/(y^2))*((x^2y^2)/(10x^3))=(20/1)(1/10)x^(5+2-3)y^(-2+2)}}}
{{{((20x^5)/(y^2))*((x^2y^2)/(10x^3))=2x^(4)y^(0)}}}
{{{((20x^5)/(y^2))*((x^2y^2)/(10x^3))=2x^(4)}}}