Question 339456
{{{(1.90x10^(-2))=(x^2)/(.295-x)}}}
{{{0.019*(0.295-x)=x^2}}}
{{{x^2=0.005605-0.0190x}}}
{{{x^2+0.019x-0.005605=0}}}
Use the quadratic formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-0.019 +- sqrt( (0.019)^2-4*1*(-0.005605) ))/(2) }}} 
{{{x = (-0.019 +- sqrt( 0.022781 ))/(2) }}} 
Complete the calculation to get the final answers.