Question 339771
let the number be x
{{{(x/2)^2-2x=5}}}
{{{(x^2/4)-2x=5}}}
{{{(x^2-8x)/4 = 5}}}
{{{(x^2-8x)=20}}}
x^2-8x-20=0
x^2-10x+2x-20=0
x(x-10)+2(x-10)=0
(x-10)(x+2)=0
number = 10 OR -2