Question 339691
Let {{{a}}} = number of $5's
Let {{{b}}} = number of $1's
given:
(1) {{{a + b = 119}}}
(2) {{{5a + b = 347}}}
Subtract (1) from (2)
(2) {{{5a + b = 347}}}
(1) {{{-a - b = -119}}}
{{{4a = 228}}}
{{{a = 57}}}
and, since
{{{a + b = 119}}}
{{{57 + b = 119}}}
{{{b = 62}}}
There are 57 $5's and 62 $1's
check:
(2) {{{5a + b = 347}}}
(2) {{{5*57 + 62 = 347}}}
{{{285 + 62 = 347}}}
{{{347 = 347}}}