Question 339469
let F=Number of $5 bills
let T=Number of $10 bills
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Given
expression 1: T < F
expression 2: 5*F+10*T=460
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Solve for F in the second expression
F=(460-10*T)/5=92-2*T
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since we know that T is less than F then
{{{ T<F=92-2*T}}}
3*T<92
T<92/3=30.667 but since we are dealing with whole numbers

T=30
substituting T=30 in F=92-2*T=92-60=32
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lets check
Choose values of T around T=30
if T=29 then F=92-2*29=34 So {{{T<F=true}}}
if T=31 then F=92-2*31=30 but {{{T<F}}} no longer holds true
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so the pivot point for {{{T<F}}} is T=30 which means F=32