Question 339442
{{{log6 x + log6 (2x+1)=2 }}}
{{{log6 x(2x+1)=2 }}}
{{{2x^2+x = 6^2 }}}
{{{2x^2+x = 36 }}}
{{{2x^2+x-36 = 0 }}}
x={4, -4.5}
The negative solution is extraneous, throw it out leaving:
x = 4
.
Details of quadratic to follow:
*[invoke quadratic "x", 2, 1, -36 ]