Question 338991
Step 1.) Find the appropriate kinematic equation: You are given Δy (the height, 19 meters), the acceleration of gravity, and you are trying to solve for the initial velocity. They didn't give you time. I would go with v^2 = v0^2 + 2gΔy.

Step 2.) Plugging the equation in:
v = 0 (it's reasonable to think that the speed at maximum height is 0; the stone goes up at a certain speed, stops, and then falls down)
g = -3.7 (the acceleration is given in the problem)
Δy = 19 (the height is given in the problem)
Find v0 (the initial velocity)

v^2 = v0^2 + 2gΔy
0^2 = v0^2 + 2(-3.7)(19)
0 = v0^2 + (-140.6)
140.6 = v0^2
v0 ≈ 11.857 m/s