Question 339239
A basketball player has a 70% free throw shooting average, which can be interpreted to mean that the probability of his hitting any single free throw is 0.7 or 7/10. 
Assume that free throws are independent events, so that what happens on one free throw doesn't affect the outcome of the next.
What is the probability that in shooting five free throws he hits at least one?
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P(hits at least one) = 1 - P(misses all five)
= 1 - 0.3^5
= 1 - 0.0024
= 0.9976
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Cheers,
Stan H.
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