Question 339212
{{{sqrt(x^2+16x+64)=sqrt(x^2+8x+8x+64)=sqrt(x(x+8)+8(x+8))=sqrt((x+8)(x+8))=sqrt((x+8)^2)=abs(x+8)}}}



So {{{sqrt(x^2+16x+64)=abs(x+8)}}}



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