Question 338132
Solving this for y yields {{{y=x^2/4+x+2}}}

This parabola has axis parallel to the y axis and has vertex at (-2,1)

p=1 and the focus is at (-2,2) and the directrix at (-2,0). The directrix is the x-axis.

Parametrically, it can be represented by 

{{{x(t)=2t-1}}}

{{{y(t)=t^2+t+5/4}}}

See, if we solve x for t, we get {{{(x+1)/2}}}

Sub into y and get:

{{{((x+1)/2)^2+((x+1)/2)+5/4=x^2/4+x+2}}}