Question 339091
{{{6/(x^2-3x)}}} * {{{(x^2-9)/(9x)}}}
:
The 1st denominator and the 2nd numerator will factor
{{{6/(x(x-3))}}} * {{{((x-3)(x+3))/(9x)}}} 
:
Cancel (x-3)
{{{6/x}}} * {{{((x+3))/(9x)}}} 
:
3 into 6 and 9
{{{2/x}}} * {{{((x+3))/(3x)}}} = {{{(2(x+3))/(3x^2)}}}