Question 339089
Factor:
{{{8x^2-50}}} 
The facors of 8 are:
1X8 = 8
2X4 = 8
The factors of 50 are:
1X50 = 50
2X25 = 50
5X10 = 50
2X5X5 = 50 Discard this as you need only two factors.
Notice that there is no middle term in the given expression so in the two factors of the form:
{{{(ax+b)*(cx+d)}}} you must have a*d = b*c in order for the middle term to drop out.
so you would choose:
a = 4 and d = 5
b = 2 and c = -10 so you get...
{{{(4x-10)(2x+5)}}} and when you FOIL these...
{{{highlight((4x-10)(2x+5)) = 8x^2+20x-20x-50}}} = {{{8x^2-50}}}