Question 338967
Two cars enter the Florida Turnpike at Commercial Boulevard at 8AM, each heading for Wildwood. 
One car's average speed is 10 miles per hour more than the other's. 
THe faster car arrives at Wildwood at 11AM, 1/2 hour before the other car. 
------
Faster car DATA:
time = 3 hrs ; rate = x+10 mph ; distance = rt = 3(x+10) miles
-----------------------------
Slower car DATA:
time = 3.5 hrs ; rate = x mph ; distance = rt = 3.5x miles
-------------------
What is the average speed of each car? How far did each car travel?
==================
Equation:
distance = distance
3(x+10) = 3.5x
3x+30 = 3.5x
0.5x = 30
x = 60 mph (rate of the slower car)
x+10 = 70 mph (rate of the faster car)
===========================================
Cheers,
Stan H.