Question 338902
a carton of eggs contains 12 eggs, 3 of which are cracked. what is the chance that when selecting five of these eggs for hard boiling, two of them are cracked?
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P(a random egg being cracked) = 3/12 = 1/4
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Now, binomial problem with p = 1/4 and n = 5
P(x=2) = 5C2(1/4)^2(3/4)^3 = binompdf(5,1/4,2) = 0.2637
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Cheers,
Stan H.