Question 338878
{{{x+y=28}}} Start with the first equation.



{{{x+highlight((2x-5))=28}}} Plug in {{{y=2x-5}}} into the second equation. In other words, replace each {{{y}}} with {{{2x-5}}}. Notice we've eliminated the {{{y}}} variables. So we now have a simple equation with one unknown.



{{{3x-5=28}}} Combine like terms on the left side



{{{3x=28+5}}}Add 5 to both sides



{{{3x=33}}} Combine like terms on the right side



{{{x=(33)/(3)}}} Divide both sides by 3 to isolate x



{{{x=11}}} Divide



Since we know that {{{x=11}}} we can plug it into the equation {{{y=2x-5}}} (remember we previously solved for {{{y}}} in the first equation).



{{{y=2x-5}}} Move onto the second equation.



{{{y=2(11)-5}}} Plug in {{{x=11}}}



{{{y=22-5}}} Multiply



{{{y=17}}} Combine like terms 



So the solutions are {{{x=11}}} and {{{y=17}}}



This means that the two numbers are 11 and 17



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