Question 338742
The area of the top and bottom circular portion of the cylinder is,
{{{Ac=pi*R^2}}}
The area of the body is calculated using the radius and the height,as if you were cutting it lengthwise and unrolling it into a rectangle.
{{{Ab=(2*pi*R)*H
Putting it all together,
{{{A=2Ac+Ab}}}
{{{A=2*pi*R^2+2*pi*RH}}}
{{{A=2*pi*(R^2+RH)}}}
{{{A=2*pi*(D^2/4+(DH)/2)}}}
{{{A=pi*(D^2/2+DH)}}}
{{{A=pi*(68^2/2+68*120)}}}
{{{A=10472*pi}}}{{{mm^2}}}