Question 338749
Express as a sum, difference, and product of logarithms, without using exponents.
log[b]√((m^2p^4)/(n^2b^9)) 
I am at a loss, I have no clue on how to do this. Thank you in advance and GOD Bless!
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Is it {{{log(b,sqrt(m^2p^4/n^2b^9))}}} ??
If so,
= {{{log(b,sqrt(bm^2p^4/n^2b^10))}}}
= {{{log(b,sqrt(m^2p^4/n^2b^10)*sqrt(b))}}}
= {{{log(b,mp^2/nb^5)*sqrt(b))}}}
= {{{(log(m) + 2log(b) - log(n) - 5log(b))*(1/2)log(b)}}} all logs base b
= {{{(log(m) + 2 - log(n) - 5)*(1/2)}}} since {{{log(b,b) = 1}}}
= log(m)/2 - log(n)/2 - 3/2
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PS To which god do you refer?