Question 338751
let the 100% alcohol required be x liters
40 % 6 liters
100% x liters
60%% (x+6 ) liters
..
100x+40*6 = 60*(x+6)
100x+240=60x+360
100x-60x=360-240
40x= 120
divide by 40
x= 3 liters
alcohol required