<PRE><B>Question 338724</B>
A group of campers and one group leader left a campsite in a canoe. 
They traveled at an average rate of 10 km/h.
1st Group DATA:
rate = 10 km/h ; distance = x km ; time = d/r = x/10 hrs
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Two hours later, the other group leader left the campsite in a motorboat.
He traveled at an average rate of 22 km/h.
Group Leader DATA:
rate = 22 km/h ; distance = x km ; time = d/r = x/22 hrs
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A. How long after the canoe left the campsite did the motorboat catch up with it?
Group time - Leader time = 2 hr
x/10 - x/22 = 2 
Multiply thru by 110 to get:
11x - 5x = 220
6x = 220
x = 110/3 = km
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canoe total time = x/10 = (110/3)/(10) = 11/3 = 3 hrs and 40 minutes
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B. How long did the motorboat travel?
motorboat time = x/22 = (110/3)/22 = 1 hr 40 minutes
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Cheers,
Stan H.
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