<PRE><B>Question 338556</B>
 The width of a rectangle is 4 cm less than its length. If the area of the rectangle is 87cm^2 what are the dimensions of the rectangle? Round to the nearest thousandth. 
I have figured out the answer as 
Length = 11.539
Width = 7.539 
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Area = L*W
L = W+4
Area = (W+4)*W = 87
W^2 + 4W = 87
W^2 + 4W - 87 = 0
*[invoke solve_quadratic_equation 1,4,-87]
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W = x  (ignore the negative solution)
W = 7.53939 ...
L = 11.53939...</PRE>