Question 38792
One number is x+3
Another number is x
Equation
{{{1/x+1/(x+3)=0.5}}}
[(x)+(x+3)]=0.5[(x)(x+3)]
{{{2x+3=0.5(x^2+3x)}}}
{{{2x+3=0.5x^2+1.5x}}}
{{{0.5x^2-0.5x-3=0}}}
{{{x^2-x-6=0}}}
Fator you get x=-2 and x=3
Hence, the numbers are 3 and (3+3)=6.
PAul.