Question 338460
Let s=speed, t=time, d=distance
st=d
sue's speed = 1/30 lap/sec, george's=1/50
the distance is in laps
time is in secs.
t=d/s The time of both of them will be equal when george is lapped.
Let x=number of laps.
.
(x+1)/(1/30)=x/(1/50)
(x+1)/50=x/30
3(x+1)=5x
3x+3=5x
2x=3
x=3/2 laps
50 * 3/2 = 75 sec. Next time they will be side by side.
.
Ed