Question 338420
{{{(c-5)/4}}}{{{""=""}}}{{{3}}}
<pre><font color = "indigo"><b>
When you do the same thing to both sides of an equation,
you get another equivalent equation.

So let's multiply both sides of the equation by {{{red(4)}}}

{{{red(4)}}}{{{""*""}}}{{{(c-5)/4}}}{{{""=""}}}{{{red(4)}}}{{{""*""}}}{{{3}}}

Now the {{{4}}}'s will cancel out on the left and the right side becomes {{{12}}} because it's {{{"4×3"}}}

{{{red(cross(4))}}}{{{""*""}}}{{{(c-5)/cross(4)}}}{{{""=""}}}{{{12}}}

So all that's left is

{{{c-5}}}{{{""=""}}}{{{12}}}

When you do the same thing to both sides of an equation,
you get another equation.

This time let's add 5 to both sides of the equation:

{{{c-5+red(5)}}}{{{""=""}}}{{{12+red(5)}}}

Now the {{{-5}}} and the {{{""+5}}} cancel out on the left,
and the right becomes {{{17}}} because ut's {{{12+5}}}

{{{c-cross(5)+red(cross(5))}}}{{{""=""}}}{{{17}}}

So all that's left is

{{{c=17}}}

and that is the answer.  Now we can check to make sure it's right.

Start with the original:

{{{(c-5)/4}}}{{{""=""}}}{{{3}}}

Susbtitute {{{17}}} for {{{c}}}

{{{(17-5)/4}}}{{{""=""}}}{{{3}}}

We put {{{12}}} in place of the {{{17-5}}}

{{{12/4}}}{{{""=""}}}{{{3}}}

Now we divide the {{{12}}} by the {{{4}}}, and we get

{{{3}}}{{{""=""}}}{{{3}}}

And since the numbers on both sides of the equal sign
are the same, we know we did it correctly, and the
answer is {{{c=17}}}.

Edwin</pre>