Question 338220
This is a systems of equations problem.
Let x=the larger smaller and y=the smaller number.
{{{x-y=4}}} and {{{2y-4x=-28}}}  Solve the first equation for x, so that you get x=y+4.  This can now be substituted for x in the second equation.
{{{2y-4(y+4)=-28}}} Solve for y and this will give you the smaller number.
{{{2y-4y-16=-28}}} distributing the -4
{{{-2y-16=-28}}} combining like terms
{{{-2y=-12}}} add 16 to both sides
{{{y=6}}} dividing both sides by -2
the smaller number is six, making the larger number 10.  You can check this by substituting 10 and 6 in the second equation to see if you get -28.
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