Question 338203
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Use the definition of logarithms.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \log_b(x) \ \ \Rightarrow\ \ b^y\ =\ x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 1.2553\ \approx\ \log_{10}(18) \ \ \Rightarrow\ \ 10^{1.2553}\ \approx\ 18]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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