Question 338166
I need to find the steps to from 
(7√(2*2*3))/6 to 7/3 √3 
I have been working on it for two days now. I just don't get it.



let's see if I can figure it out
sqrt = square root = √


(7 * sqrt(2 * 2 * 3))/6 to 7/3 * sqrt(3)
(if I mistyped or misinterpreted, I apologize)


numerator:
7 * sqrt(12) = 7 * sqrt(4 * 3) = 7 * sqrt(2 * 2 * 3) (factoring)
7 * sqrt(12) = 7 * 2 * sqrt(3) 
(there were two 2's inside the square root, sqrt(4) = 2)



denominator:
6 = 2 * 3


the 2's in the numerator and denominator cancel out


left with:
7/3 * sqrt(3)