Question 338054
{{{(2x-2y+2)/(36-3x)=(2(7)-2(2)+2)/(36-3(7))=(14-4+2)/(36-21)=12/15=4/5}}}



So {{{(2x-2y+2)/(36-3x)=4/5}}} when {{{x=7}}} and {{{y=2}}}



So there's either a typo in the problem or in the answer. Double check to make sure that there are no typos.



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Jim