Question 338016
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*[tex \LARGE 23.3\text{ km/h }\approx\ 6.472\text{ m/sec}]


Instantaneous velocity as a function of time is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v(t)\ =\ at\ +\ v_o]


Here, initial velocity, *[tex \Large v_o\ =\ 0], *[tex \Large t\ =\ 8.4] sec, and *[tex \Large v(t)\ =\ 6.472] m/sec


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6.472\ =\ 8.4a]


Solve for *[tex \Large a]


Then, distance traveled is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ s(t)\ =\ \frac{1}{2}at\ +\ v_ot\ +\ h_o]


*[tex \Large h_o\ =\ 0], *[tex \Large v_o\ =\ 0], *[tex \Large t\ =\ 8.4], and *[tex \Large a] is what you calculated above.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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