Question 337942
#1
First, simplify the equation by combining like terms.
{{{2x^2+2x-4=36}}}
This is a quadratic equation (the x is squared) so you have to set the equation equal to zero by subtracting 36 from both sides.
{{{2x^2+2x-40=0}}}  Everything here can be divided by 2 to make the problem simpler.  You can do this in a equation as long as you do it to both sides.
{{{x^2+x-20=0}}}  Now you can factor this quadratic to find the answer most easily.
{{{(x+5)(x-4)=0}}} This is the equation factored.  You need to look for two numbers that multiply to 20 and add or subtract to 1 (the middle number). These numbers are 4 and 5.
Then set each equation equal to 0.
{{{x+5=0}}}{{{x-4=0}}} Solve each for x.
x=-5, x=4.  These are your answers.  Most quadratics have two answers.
#2 isn't an equation, so you can't solve it.  I would assume there is some info missing.  If you need more help on factoring, please ask.