Question 337746
The perpendicular distance from the center to the line {{{x=3}}} is the radius.
{{{R=3-(-2)=5}}}
Use the general equation of a circle centered at (h,k) with radius R.
{{{(x-h)^2+(y-k)^2=R^2}}}
{{{x-(-2))^2+(y-(-7))^2=5^2}}}
{{{highlight((x+2)^2+(y+7)^2=25)}}}
{{{x^2+4x+4+y^2+14y+49=25}}}
{{{x^2+4x+y^2+14y+28=0}}}