Question 337700
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<b>Step 1:</b> Determine the slope of the graph of the given equation.  You can proceed either of two ways.  1:  Solve the equation for *[tex \Large y] in terms of everything else, which is to say, put it into slope-intercept form *[tex \Large y\ =\ mx\ +\ b]. Then determine the slope by inspection of the coefficient on *[tex \Large x].  OR 2:  Divide the coefficient on *[tex \Large x] by the coefficient on *[tex \Large y] and then take the additive inverse of that fraction.


<b>Step 2:</b>  Determine the negative reciprocal of the slope calculated in step 1 because:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


<b>Step 3:</b>  Use the point-slope form of an equation of a line to write your desired equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.


<b>Step 4:</b> Solve the derived equation for *[tex \Large y] in terms of everything else to put it into slope-intercept form *[tex \Large y\ =\ mx\ +\ b].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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