Question 337650
DRAW YOU LADDER AND LABLES TO YOUR PYTHAGOREAN THEOREM:

A^2+B^2=C^2

FIRST LADDER:  C^2=24^2+A^2

SECOND LADDER: C^2=15^2+(A+13)^2

PLUG IN:  24^2+A^2 = 15^2+(A+13)^2

24^2+A^2 = 15^2+(A+13)(A+13)


24^2+A^2 = 15^2+A^2+26A+13^2

24^2+A^2-A^2 =15^2+A^2+26A+13^2-A^2

24^2 = 15^2+26A+13^2

24^2-15^2-13^2= 26A

576-225-169 = 26A

182/26 = A

A = 7 FEET


GO BACK AND PLUG IN THE THEOREM FOR EACH LADDERS FOR VARIFICATION. 

 C^2=24^4 + A^2  C^2=576+7^2=49+576=625  

C=SQRT625 = 25     SO THE LADDER IS 25 FEET ANSW.( DO FOR THE OTHER TOO SHOULD BE THE SAME... C^2=15^2+(A+13)^2)